# Line slope calculator 8x+9y=80

**Straight line given by points A[1; 8] and B[10; 0]**

## Calculation:

**Slope-intercept form of line:**y = -0.8889x+8.8889

**Canonical form of the line equation:**8x+9y-80 = 0

**Parametric form of the line equation:**

x = 9t+1

y = -8t+8 ; t ∈ R

**Slope:**m = -0.8889

**Slope angle of line: φ =**-41°38'1″ = -0.7266 rad

**X intercept:**x

_{0}= 10

**Y intercept:**y

_{0}= q = 8.8889

**Distance line from the origin:**d

_{0}= 6.6436

**The length of the segment AB: |AB| =**12.0416

**Vector: AB =**(9; -8)

**Normal vector: n =**(8; 9)

**Midpoint of the segment AB: M =**[5.5; 4]

**Perpendicular Bisector equation:**9x-8y-17.5 = 0

**Vector OA = (1; 8) ; |OA| = 8.0623**

**Vector OB = (10; 0) ; |OB| = 10**

**Scalar product OA .OB = 10**

**Angle ∠ AOB = 82°52'30″ = 1.4464 rad**