# Line slope calculator 5x-6y=15

**Straight line given by points A[3; 0] and B[9; 5]**

## Calculation:

**Slope-intercept form of line:**y = 0.8333x-2.5

**Canonical form of the line equation:**5x-6y-15 = 0

**Parametric form of the line equation:**

x = 6t+3

y = 5t ; t ∈ R

**Slope:**m = 0.8333

**Slope angle of line: φ =**39°48'20″ = 0.6947 rad

**X intercept:**x

_{0}= 3

**Y intercept:**y

_{0}= q = -2.5

**Distance line from the origin:**d

_{0}= 1.9206

**The length of the segment AB: |AB| =**7.8102

**Vector: AB =**(6; 5)

**Normal vector: n =**(5; -6)

**Midpoint of the segment AB: M =**[6; 2.5]

**Perpendicular Bisector equation:**6x+5y-48.5 = 0

**Vector OA = (3; 0) ; |OA| = 3**

**Vector OB = (9; 5) ; |OB| = 10.2956**

**Scalar product OA .OB = 27**

**Angle ∠ AOB = 29°3'17″ = 0.5071 rad**